Fluid and Gas Law Pracitce Test Answers
1) D
2) B
3) B
4) C
5) c
6) A
7) D
C
9) B
10) A
11) D = m/v (but you need it in g and mL to compare to water’s…so you gotta convert) 560g/2000mL = .28 g/mL. Because the density of the object is less than the density of water, the object will float.
12) When temperature increases, pressure increases in a rigid container. This is because as the temperature increases, the particles are moving faster and faster. This means that they hit eachother and the walls of their containers more often and harder, thus causing more force on the area of the container which means more pressure. Since the walls don’t move in a rigid container, they stay in place, thus the pressure increases.
13) When volume increases pressure decreases, and when volume decreases pressure increases. This is because as the volume increases, the walls spread further apart and so the particles have more time between collisions, losing some of their energy and thus they hit less hard and pressure decreases. Also, if the volume is reduced, the walls are closer together and so the particles hit more often, causing more pressure.
14) Pascal’s principle states that a pressure applied to one part of a fluid is experienced throughout the entire fluid. This works in hydraulics because both pistons are connected with a fluid (gas or liquid) contained within them. Thus when you push down on one piston (applying a pressure) you effectively push up on the other one because that pressure is felt throughout.
15) f1/a1 = f2/a2 .125/x=.045/300 ans = 833.333N
16) T in K p1= 235, T1= 305, t2 = 259 t1/p1=t2/p2 305/235=259/x ans 199.55kPa
17) change units (1 atm =101.3 kPa) mL into L so V1=.45L P1=1.5 and P2=130kPa* (1atm/101.3kPa)
p1*v1=p2*v2 .45*1.5=1.28x ans = .53 L
18) t1=297, v1=4, t2= 331 t1/v1=t2/v2 297/4=331/x ans 4.46L
19) a. decreasing by half b. increasing 4 times c. decreasing by 1/8 d. increasing by 10
20) a. 344.2 b. 112.5 c. 316 d. 1.2
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